These are pre-lab questions for my physical chemistry lab. If someone could expl

Question

These are pre-lab questions for my physical chemistry lab. If someone could explain the steps, that would be very helpful! Thank you so much.

1. Ambient pressure is measured to be 756.5mm Hg using the barometer. The height of Hg for the Utube manometer is measured to be 310.4mm Hg for the side connected to the vacuum manifold and -305.9mm Hg on the side exposed to room pressure. Wat is the pressure of the system? (Neglect temperature corrections for this question).

Explanation / Answer

1. Let pressure of the system be P

given height of mercury at the side of the manifold, h1 = 310.4 mm Hg

height of mercury on the side open to atmosphere, h2 = -305.9 mm Hg

density of Hg = 13593 kg/m^3

ambient pressure Po = 756.5 mm

so P + rho*g*h1 = Po + rho*g*h2

P = Po + rho*g(h2 - h1)

but Po = rho*g*756.5

so P = ro*g(756.5 - 305.9 - 310.4) mm = rho*g(140.2 mm ) = rho*g(0.1402) = 18695.295666 Pa

so P = 18695.295666 Pa = 140.2 mm Hg

2. by plotting the data on excel

108.4 533

101.6 378

94.3 254

79.4 113

53.7 20

assuming T to be y and P to be x

error by LINEST function is 0.099174942

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