A block of mass m 5.3 kg is pulled up a 241 incline as in the figure below with

Question

A block of mass m 5.3 kg is pulled up a 241 incline as in the figure below with a force of magnitude F= 38 N. (a) Find the acceleration of the block if the incline is frictionless. (Give the magnítude of the acceleration.) 3.18 m/s? (b) Find the acceleration of the block if the coefficient of kinetic friction between the block and incline is 0.12. (Give the 1.74 Your response differs from the correct answer by more than 10%. Double check your calculations. m/s' elp? IRead It o 22 points I Previous Answers SerCP1 4P.026 A girl exerts a horizontal force of 137 N on a box with a mass of 34.7 kg HINT ht'e the magnitude of the static friction force (in N)?

Explanation / Answer

Given,

m = 5.3 kg ; theta = 24 deg ; F = 38 N

a)The net force acting on the block is:

Fnet = F - W

Fnet = F - mg sin(theta)

Fnet = 38 - 5.3 x 9.8 x sin24 = 16.87

Fnet = ma => a = Fnet/m

a = 16.87/5.3 = 3.18 m/s^2

Hence, a = 3.18 m/s^2

b)u = 0.12

When the friction also acts, then the net force is :

Fnet = F - mg sin(theta) - u mg cos(theta)

Fnet = 38 - 5.3 x 9.8 s sin24 - 0.12 x 5.3 x 9.8 x cos24 = 11.18 N

a = Fnet/m = 11.18/5.3 = 2.11 m/s^2

Hence, a = 2.11 m/s^2

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