Consider a domain where density varies based on the given equation The velocity
ID: 3280276 • Letter: C
Question
Consider a domain where density varies based on the given equation The velocity field in the domain is defined by the following equation In the above equations, t denotes time and (x,y,z) denotes position inside the domain. 1. Consider the questions below at a given position Xo = (5,30,11) in the domain at a time to = 30 s a. Find the time rate of change of density of a material particle lowing through the domain at point xo at time to. [5] Is this a steady flow? Why, or why not? [1] Based only on your theoretical understanding of fluid mechanics, is this a compressible flow? Why, or why not? [1] b. c. Mach number of this flow. Based on Mach number data, would you predict the flow to be compressible? 13+1] Find the vorticity vector at point xo at time to. Is this flow rotational at that point and time? If yes, what is the angular velocity of that rotation? [3+1/2+1/21 e.Explanation / Answer
1. given density variation
rho = (2x - 3y)e^(-t^2)
and velocity field
v = 2tx i + 3x^2 j + (2z - y) k
where i j , k are unit vectors along x , y and z directions respectively
also, xo = 5
yo = 30
zo = 11
to = 30 s
a. d(rho)/dt = (2x - 3y)*e^(-t^2)*(-2t) = 2t(3y - 2x)e^(-t^2)
so at xo, yo, zo, to
d(rho)/dt = 3*30(3*30 - 2*5)e^(-30^2) = 9.824*10^-388
b. for a steady flow, d(rho)/dt = 0
i.e. there is no time dependance of density
but as we can see
d(rho)/dt = 2t(3y - 2x)e^(-t^2) != 0
hence
this is not a steady flow
c. as density is a fuinction of time, this means that density changes with time, hence for a flow with time dependent density changes, it is a compressible flow
d. if the material is assumed to be air, ideal gas at 30 C
then , v = 2tx i + 3x^2 j + (2z - y) k
at xo, yo, zo, to
vo = 2*30*5i + 3*25 j + (2*11 - 30)k
vo = 300i + 75j - 8k
so |vo| = 309.336 m/s
now speed of sound in air at 30 C = 334 m/s
hence
mach number = m = |vo|/334 = 0.926
based on mach number the flow is compressible as at mach number close to 1, air at normal standard temperature becomes a compressible flow problem
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.