According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M

Question

According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. [Round your answers to three decimal places, for example: 0.123]

Compute the probability that a randomly selected peanut M&M is not blue.



Compute the probability that a randomly selected peanut M&M is green or blue.



Compute the probability that two randomly selected peanut M&M’s are both yellow.



If you randomly select three peanut M&M’s, compute that probability that none of them are orange.



If you randomly select three peanut M&M’s, compute that probability that at least one of them is orange.

  

Explanation / Answer

a)

P( not blue) = 1- P(blue)

= 1 - 23%

= 77% = 0.77

b)

P(G) + P(B) = 0.15 + 0.23

= 0.38

c)

assume 100 M&M’s

both yellow = 15/100 * 14/99 = 0.212

d)

assume 100 m&m’s

none of them orange

= 77/100 * 76/99 * 75/98

= 0.452

e)

atleast 1 orange = 1- none of them orange

= 1 - 0.452

= 0.548

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