At Anytownville College, 45% of all students are enrolled in an advanced statist

Question

At Anytownville College, 45% of all students are enrolled in an advanced statistics class, and 11% of all students are seniors. It is also known that 65% of the seniors are enrolled in an advanced statistics class. Round your answers to 4 decimal places. a. Initech is offering an internship to a Anytownville College student who is either a senior or is enrolled in an advanced statistics class. What is the probability that a student enrolled at Anytownville College is eligible for this internship? b. What is the probability that a student enrolled in an advanced statistics class at Anytownville College is a senior? Submit Answer Tries 0/5 c. Given that a student selected at random is not a senior, what is the probability that he/she is enrolled in an advanced statistics class?

Q8 At Anytownville College, 45% of all students are enrolled in an advanced statistics class, and 11% of all students are seniors. It is also known that 65% of the seniors are enrolled in an advanced statistics class. Round your answers to 4 decimal places. a. Initech is offering an internship to a Anytownville College student who is either a senior or is enrolled in an advanced statistics class. What is the probability that a student enrolled at Anytownville College is eligible for this internship? Submit Answer Incorrect. Tries 1/5 Previous Tries b. What is the probability that a student enrolled in an advanced statistics class at Anytownville College is a senior? Submit Answer Incorrect. Tries 1/5 Previous Tries c. Given that a student selected at random is not a senior, what is the probability that he/she is enrolled in an advanced statistics class? Submit Answer Incorrect. Tries 1/5 Previous Tries

Explanation / Answer

let A is probability of being in advance stat and B is that of being senior

a) probability =P(A)+P(B)-P(AnB) =0.45+0.11-0.11*0.65=0.4885

b)probabilty =P(B|A ) =0.11*0.65/0.45=0.1589

c)P(A|Bc) =P(AnBc) /P(Bc) =(0.45-0.11*0.65)/(1-0.11)=0.4253

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