How to do problem number 6? 5. An urn contains 10 balls, 4 red and 6 blue. A sec

Question

How to do problem number 6?

5. An urn contains 10 balls, 4 red and 6 blue. A second urn contains 16 red balls and an unknown number of blue balls. A single b is drawn from each urn and the probability that both balls are the same color is 0.44. How many blue balls are there in the second urn? 6. There are 4 yellow peppers, 6 green peppers and 6 yellow squashes in a basket. How many green squashes should be put in the basket if color and type of vegetable should be independent when choosing a random piece from the basket?

Explanation / Answer

Question 6

yellow peppers = 4

Green pappers = 6

Yellows squasehs = 6

Let say there are x green squashes must be added to the basket but it makes color and type of vegatable independent os each other.

that mean if are picking any object from the basket

Pr (Color l Type of vegatable) = Pr (Color l different type of vegetable)

for ex. Pr (Green vegatable l squash) = Pr(Green vegatable l peppers)

=> X/ (6 + x) = 6/10

10 X = 36 + 6X

X = 9

so , 9 green squashes must be added.

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