How to do question 5 and 6, and is my answer correct for question 2.3.4Thx A sol

Question

How to do question 5 and 6, and is my answer correct for question 2.3.4Thx



A solution of sodium hydroxide was standardized by titrating known volumes of the above KHP solution. The resulting data are summarized in the table below Initial KHP buret reading Final KHP buret reading Initial NaOH buret reading Final NaOH buret reading RUN 1 4.98 40.73 3.14 24.62 RUN 2 0.5 33.18 3.04 22.69 What is the concentration (M) of the NaOH for Run 1 of the standardization? Question 2 Enter Your Answer: 0.10752 What is the concentration (M) of the NaOH for Run 2 of the standardization? Question 3 Enter Your Answer: 0.10744 What is the average concentration (M) of the NaOH for the above two runs? Question 4 [Note: The accuracy of the average concentration of NaOH is critical in the answers to most of the subsequent questions. Enter Your Answer: 0.10748 What is the average deviation of the concentration of the NaOH for the above two runs ? Question 5 Enter Your Answer: What is the percent deviation of the concentration of the NaOH for the above two runs Question 6 Enter Your Answer:

Explanation / Answer

Run 1 Result: 0.10752M

Run 2 Result: 0.10744M

Average of both runs = 1/2 * (0.10752+0.10744) = 0.10748

Average Deviation = 1/N * |Sum(Xi-mean)|

Here N=2 and mean = 0.10748

substituting the values we get

Average Deviation = 1/2 * ( |0.10752-0.10748| + |0.10744-0.10748|) = 4 * 10^(-5)

Percent Deviation = Average Deviation/Mean * 100 = 4 * 10^(-5)/0.10748 * 100 = 0.03721%

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