An ANOVA test can be done to compare if the average numbers of dinners sold by t
ID: 3305227 • Letter: A
Question
An ANOVA test can be done to compare if the average numbers of dinners sold by three restaurants are identical or not with the level of significance is 0.05. Alternatevly, I decided to do 3 all possible two-sample tests for the hypothesis testing of: H0: h1 = h2 = h3 vs. h1: Not all of the mean values are equal. The, what should be the true level of significance (or Type 1 error) of the hypothesis test? (choose a closet one)
A.) 15%
B.) 25%
C.) 19%
D.) 75%
E.) 81%
SF-Susi SF-Taco SF-Pizza
13 10 18
12 12 16
14 13 17
12 11 17
17
Explanation / Answer
here as level of significance =0.05
therefore probability of type 1 error =P(at least one test shows signfiicance) =1-P( none of 3 shows significance)
=1-(!-0.95)3 =~0.15
hence option A is correct
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