1- why the percentage error for the superpsition theorem be close to 0? why is n

Question

1- why the percentage error for the superpsition theorem be close to 0? why is not exactly 0?
2- The theoretical and measured reactance should be the same, If they arent, what could cause the variation? 1- why the percentage error for the superpsition theorem be close to 0? why is not exactly 0?
2- The theoretical and measured reactance should be the same, If they arent, what could cause the variation?
2- The theoretical and measured reactance should be the same, If they arent, what could cause the variation?

Explanation / Answer

Answers for both 1 and 2 are interlinked.

The percentage error in the superposition theorem represents the variation in the measurement of theoritical and measured/observed values. It will be zero only and only if both the values are same. But there is a very small difference in tge two quantities. The reason is as follows:

Theoritical values are the values which are taken as standards for completely ideal or perfect circuits. That is, there are no flaws in the circuit whose value are considered as theoritical values (reactance, let say). But in actual practice, no circuit is ideal. There always are some imperfections due to any factor ( EM interference, air resistance, wires characterstics etc) which led to a variation in the observed value as compared to the theritical value.

This is the reason why the theoritical and measured reactance of a circuit or power line are not exactly same and for the same reason, the percentage error for the superposition theorem is always tends to zero, but is not exactly equal to zero.

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