8:23 PM webassign.net ..1 T-Mobile A parallel-plate capacitor with area 0.400 m2

Question

8:23 PM webassign.net ..1 T-Mobile A parallel-plate capacitor with area 0.400 m2 and plate separation of 2.00 mm is connected to a 3.00 V battery. (a) What is the capacitance? (b) How much charge is stored on the plates? (c) What is the electric field between the plates? N/C (d) Find the magnitude of the charge density on each plate. C/m2 (e) Without disconnecting the battery, the plates are moved farther apart. Qualitatively, what happens to each of the previous answers? Need Help? Show My Work (Optional) O A certain storm cloud has a potential difference of 2.00 108 V relative to a tree. If, during a lightning storm, 60.0 C of charge is transferred through this potential difference and 1.00% of the energy is absorbed by the tree, how much water (sap in the tree) initially at 25.0°C can be boiled away? Water has a specific heat of 4186 J/kg.°C, a boiling point of 100°C, and a heat of vaporization of 2.26 x 106 J/kg kg Noed Help? Show My Work(Optional)o Home My Assignments Extension Request

Explanation / Answer

Here ,

a) capcitance , C = epsilon * Area/d

C = 8.854 *10^-11 * 0.40/0.002

C = 1.77 *10^-9 F

b) charge on the plates = 3 * 1.77 *10^-9 C

charge on the plates = 5.31 *10^-9 C

c) electric field between the plates = V/d

electric field between the plates = 3/.002

electric field between the plates = 1500 V/m

d) charge denssity = charge/area of each plate

charge denssity = 5.31 *10^-9/(0.40)

charge denssity = 1.33 * 10^-9 C/m^2

e) when the plates are moved apart more , the capcitance decreases ,

which decreases the amount of charge on each plate

also, the electric field decreases and the charge density will also decrease

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