My Notes Ask Your Te 2. 14/15 points | Previous Answers Illowskyintro Stat1 9.HW

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My Notes Ask Your Te 2. 14/15 points | Previous Answers Illowskyintro Stat1 9.HW.073. An organization published an article stating that in any one-year period, approximately 11.8 percent of adults in a country suffer from depression or a depressive illness. Suppose that in a survey of 100 people in a certain town, nine of them suffered from depression or a depressive illness. Conduct a hypothesis test to determine if the true proportion of people in that town suffering from depression or a depressive illness is lower than the percent in the general adult population in the country Part (a) Part (b) Part (c) ar Part (e) Part (f) Part (g) Part (h) Part (i) Find the p-value. (Round your answer to four decimal places.) Part U)

Explanation / Answer

The statistic can be formed as (p(sample)-P)/sqrt(p*(1-p)/n). Thus the statistic is (.09-.118)/sqrt(.09*.91/100)=-0.97. and the corresponding p value is 16.6%.

As the statistic is greater than the critical value of -1.96 at a 95% confidence interval, thus the null hypothesis is accepted and thus we can't conclusively say that the true proportion of adults suffering from depression is greater ion the sample than the population.

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