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Name On n2 The data below is for the response time in tmilliseconds of three dif

ID: 3315700 • Letter: N

Question

Name On n2 The data below is for the response time in tmilliseconds of three different circuit types. ANOVA table for a one-way experiment is shown below. response time in milliseconds of three different circuit types. The RESPONSE (msec) 19 CIRCUITRY TYPE 20 25 20 21 27 40 15 18 26 17 Source DF Treatments . Error Total MS 0.046 260.9 90.8 32.6 651.7 a.) Complete the ANOVA table above. b.) State the null hypothesis c.) State the alternative hypothesis d.) Sketch in the space below an F-test ofthe null hypothesis using a 95% confidence level. e.) State whether to accept or reject Ho at alpha-.05 f.) Explain the use of the p-value in the wake of your decision to accept or reject. g.) Sketch (very roughly) the residuals vs, the circuit type and comment on the normality assumption. PLEASE PLACE ANSWERS IN ORDER BELOWANDON BACK OF THIS SHEET 2 L00.9 346.6

Explanation / Answer

Fromm Excel

b)

Null Hypothiesi:

There is no significance difference between means of three groups

c) Alternative hypothesis:

There is a significance difference between means of three groups

d) F cal=4.006

e) P value=0.0468 <0.05 we reject the Ho.

Hence claim is significant.

Anova: Single Factor SUMMARY Groups Count Sum Average Variance Country 1 5 104 20.8 7.7 Country 2 5 141 28.2 70.7 Country 3 5 92 18.4 19.3 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 260.9333 2 130.4667 4.006141 0.046484 3.885294 Within Groups 390.8 12 32.56667 Total 651.7333 14