s eat: A fast-food restaurant chain has 600 outlets in the States. The following
ID: 3315986 • Letter: S
Question
s eat: A fast-food restaurant chain has 600 outlets in the States. The following table categorizes them by city n size and location, and presents the number of populati restaurants in each category. A restaurant is to be ch random osen at from the 600 to test market a new menu. Region NE SE SW NW Population of city Under 50,000 50,000-500,000 | 30 351 15 5145 6090 150 25 0 70 30 60 o ver a. Given that the restaurant is localed in a ciy with COO b. Given that the restaurant is located in the Southeast, what c. Given that the restaurant is located in the Southwest, d. Given that the restaurant is located in a city with a e. Given that the restaurant is located in the South (either SE population over 500,000, what is the probability that it is in the Northeast? is the probability that it is in a city with a population under 50,000? what is the probability that it is in a city with a population of 500,000 or less? population of 500,000 6Tless, what is the probability that it is in the Southwest? or SW), what is the probability that it is in a city with a population of 50,000 or more?Explanation / Answer
a) P(Northeast/over 500000) = P(Northeast and over 500000) / P(Over 500,000) = (150/600) / (265/600) = 0.56603
b) P(Under 50,000/Southeast) = P(under 50000 and southeast) / P(southeast) = (35/600) / (150/600)= 35/150= 0.2333
c) P(Under 500,000/Southwest) = P(Under 500,000 and Southwest) / P(Southwest) = (85/600) / (115/600) = 0.73913
d) P(South west / Under 500,000) =P(South west and Under 500,000) / P(Under 500,000) = (85/600) / (335/600) = 0.25373
e) P(50,000 or more / either SE or SW) = P(50,000 or more and either SE or SW) / P(either SE or SW)
= (90+70+25+30)/600 / (150+115)/600 = 215 / 265 = 0.81132
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.