Given 5 bolt vendors, you wish to test the corrosion rate of their bolts. You ch

Question

Given 5 bolt vendors, you wish to test the corrosion rate of their bolts. You choose to test 50 bolts of each vendor [a total of 250 bolts]. Answer the following For an ANOVA test, what are the DoF for fTreatments, Error, Total]? D: (5, 245, 250] E: [5, 244, 2491 F: 14, 245, 249) G: 14, 246, 250] A: 15, 50, 250] B: 14, 50, 249] C: 14, 46, 50) For a Comparison test, how many pairs would need to be tested? A: 5 B: 10 H: None of these are cor rect C: 8 E: 9 D: 20 For a Comparison test, if the for a single test was 0.05 approximately what would be the overall chance of Type I error atotal? A: 0.05 C: 0.95 E: 0.095 B: 0.50 D: 0.60 F: 0.40 Indicator(s) that a factor or treatment is significant in an ANOVA used for means testing is(are): D: Large Sum of Squares A: Large associated F - score B: Large associated p - value C: Large ratio of MST and MSE E: Large df Shade in the region representing a Type II error [the dashed curve is reality] Rojoct Ho Accapt Ho Rojoct Ho

Explanation / Answer

Question 1:-

If,the treatment has k different levels,then the sum of Squares due to treatment has k-1 degrees of freedom and the error sum of squares has n-k degrees of freedom,n is total no. of observations.[RESULT]. Here,we have 5 different vendors which are treated as treatment,so k=5,n=250, so treatment df=5-1=4,error df=250-5=245 and total df=244+5=249 .So , [F] is correct option.

Question 2:-

The pairs needed to be tested is= 5C2=10 (How can I choose a pir among 5 objects :- this is the logic whic has this answer that has been given)

Question 3:-

By definition,the overall chance of type I error is 0.05 in multiple comparision test.Hence,option (A) will be correct.

Question 4:-

By definition,the treatment effects will be significant if the ratio of MST(mean sum of squares due to treatment) and MSE(mean error sum of squares) is large.So,option [C] will be correct.

Question 5:-

Type II error is accepting H0 when H0 is false.H0 is false means we are conidering red dashed curve.Accepting H0 means,the region between two "Reject H0" lines,so type II error will be the area under the red dashed curve within the region bounded by "Reject H0" lines.

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