Find a 90% confidence interval for a population mean for these values. (Round yo

Question

Find a 90% confidence interval for a population mean for these values. (Round your answers to three decimal places.) (a) n = 150, x = 0.88, s2 = 0.083 x to (b) n = 70, x = 27.8, s2 = 3.17 to (c) Interpret the intervals found in parts (a) and (b) In repeated sampling, 10% of all intervals constructed in this manner will enclose the population proportion O There is a 90% chance that an individual sample proportion will fall within the interval. 90% of all values will fall within the interval. In repeated sampling, 90% of all intervals constructed in this manner will enclose the population mean. There is a 10% chance that an individual sample proportion will fall within the interval.

Explanation / Answer

Solution:- 90% confidence interval Z = 1.645
a) n = 150, X = 0.88, S^2 = 0.083

=> X +/- Z * s^2/sqrt(n) = 0.88 +/- 1.645*0.083/sqrt(150) = (0.8689 , 0.8911)

b) n = 70, X = 27.8, S^2 = 3.17
  
=> X +/- Z * s^2/sqrt(n) = 27.8 +/- 1.645*3.17/sqrt(70) = (27.1767 , 28.4233)

c) option C. In repeated sampling, 90% of all intervals constructed in this manner will enclose the population proportion

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.