(Q #2) It is desired to test the hy significance. Assume that the population sta

Question

(Q #2) It is desired to test the hy significance. Assume that the population standard deviation is 14. Calculate the probability of committing type II error if the true population mean is 96 and a sample of 49 items is considered. (a) 0.31 pothesis that the population mean is greater than or equal to 100 at 0.05 level of (b) 0.33 (c) 0.36 (d) 0.39 (e) 0.52 Please answer all questions and show work. Will rate 100% ts at a certain university to spend yearly on campus is 650 random from two different lecture sections, average on-campus yearly hours will differ with a standard deviation of 50. Two groups of students are selected at consisting of 32 and 50 students, respectively. What is the probability that their by an amount between 20 and 25 hours? (a) 0.9747 (b) 0.0248 (c) 0.9864 (d) 0.9616 (e) 0.0496

Explanation / Answer

2)

here std error =std deviation/(n)1/2 =14/(49)1/2 =2

for 0.05 level critical z =1.6449

hence acceptance region =P(X>100-1.6449*2)=P(X>96.710)

given true mean 96; probability of type II error =P(Z>(96.710-96)/2)=P(Z>0.3551)=0.36

option C

3)

here mean differnece =0

and std deviation =(502/32+502/50)1/2 =11.319

hence probability =2*P(20<X<25)=2*((20-0)/11.319<Z<(25-0)/11.319)=2*P(1.77<Z<2.21)=2*(0.9864-0.9614)

=0.0496

option e

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.