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Based on a random sample of 20 people, the mean tip that they said they would le

ID: 3326500 • Letter: B

Question

Based on a random sample of 20 people, the mean tip that they said they would leave after a $30 meal eas $3.75 and the standard deviation was $0.25. Assume the tip amounts are normally distributed. Construct. 90% confidence interval for the population mean tip.
1. Identify the sample size, sample mean, sample standard deviation, and the appropriate test score (t or z) value for 90% confidence
2. Calculate the standard error for the mean. Round your answer to the nearest hundredths place
3. Calculate the maximum error of the mean. Round your answer to the nearest hundredth place.
4. Determine the confidence interval of the mean? Lower limit: Upper limit:
Show all work Based on a random sample of 20 people, the mean tip that they said they would leave after a $30 meal eas $3.75 and the standard deviation was $0.25. Assume the tip amounts are normally distributed. Construct. 90% confidence interval for the population mean tip.
1. Identify the sample size, sample mean, sample standard deviation, and the appropriate test score (t or z) value for 90% confidence
2. Calculate the standard error for the mean. Round your answer to the nearest hundredths place
3. Calculate the maximum error of the mean. Round your answer to the nearest hundredth place.
4. Determine the confidence interval of the mean? Lower limit: Upper limit:
Show all work
1. Identify the sample size, sample mean, sample standard deviation, and the appropriate test score (t or z) value for 90% confidence
2. Calculate the standard error for the mean. Round your answer to the nearest hundredths place
3. Calculate the maximum error of the mean. Round your answer to the nearest hundredth place.
4. Determine the confidence interval of the mean? Lower limit: Upper limit:
Show all work

Explanation / Answer

All parts are as below

CI for 90% n 20 mean 3.75 t-value of 90% CI 1.7291 std. dev. 0.25 SE = std.dev./sqrt(n) 0.05590 ME = t*SE 0.09666 Lower Limit = Mean - ME 3.65334 Upper Limit = Mean + ME 3.84666 90% CI (3.6533 , 3.8467 )
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