for problem A number 3 how do i figure it out by using the chart? the answers ar
ID: 3334399 • Letter: F
Question
for problem A number 3 how do i figure it out by using the chart? the answers are posted as well, the answer to number 3 is .4761
0.9916 0.9936 974 81 86 Problem A Student test scores from a college admissions test are normally distributed. (SEE EXCEL OUTPUT, APPENDIX 1) 1. Suppose -544 and =10. Find the probability that a student's test score is greater/ than or equal to 420 and less than or equal to 610. 494 ando The probabilityks 80that a student's testscoreisnoleu 100 2. Suppose an what value? th 3. Suppose-494 and =100. Find the probability that a student's test score is greater than 500. Suppose pr544 and -110.The probability is .60 that astudent's test scorewillw ween what two values equidistant from the mean test score? 4 and =110. Find the probability that a student's test score is less than 5. Suppose -54 380 or greater than 770. ability is 30 that a student's test score is at most Sup osep-494 and -100. The prob 6.Explanation / Answer
(According to Chegg policy, only four subquestions will be answered. Please post the remaining in another question)
1. = 544 = 110
X = 420
Z = (X - ) /
= (420 - 544) / 110
= -1.2727
Probability from tables = 0.1016.
X = 610
Z = (610 - 544) / 110
= 0.6
Probability from tables = 0.7257
=> Probability between 420 and 610 = 0.7257 - 0.1016 = 0.6241.
2. = 494 = 100
Z from tables for 0.80 = -0.8416
X = + z
= 494 - 0.8416 * 100
= 409.8400.
3. X = 500
Z = (500 - 494) / 100
= 0.06
Probability from table (right tabled) = 0.4761.
You need to reverse lookup i.e first look into the values for 0.06 and then find the row and the column number.
4. Since probability is 0.80 between the two values, it is 0.40 from the mean and 0.20 from 0. Thus we need to find the z scores such that p < 0.20 and p < 0.60.
The z scores are -0.8415 and 0.2533.
X = 544 - 0.8415 * 110 = 451.435
and
X = 544 + 0.2533 * 110 = 571.863.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.