for problems 14 through 25, (32 Points) It has always been considered dangerous
ID: 3358924 • Letter: F
Question
for problems 14 through 25, (32 Points) It has always been considered dangerous to rink and drive, but today people are asking the question, is it in fact more dangerous to text and drive? To previous 6 months who 58 had been texting this question I sampled 81 people who had been in an automobile accident in the p had either been texting while driving or drinking just prior to driving. Of these 81 people, while the accident occurred and 23 had been just prior to the accident. [Outcome of interest is 056 Cinking =.050 of interest? andl diving 15. What is the situation test situation?ona Sanle paDefend your answer 16. What is the numerical value of p 17. Calculate p (round offto 2 decimal places) es l sls ?, 32 Interpret this value 79% of the Sar@icdrople invaved in a car ace i den + Sloted while dasin 18. In English write the alternative hypothesis HA ;Tering and chinng is tenli telu to be selected oul of tht Sampled who uuen tar accident ,n Hu Pendus monts 19. What is (are) the critical valuets) for this scenario?Cy: l45 la 20. For what values ofthe test statistic would you Reject Hor ul tto Fche valuride TS21.urs 21. Calculate the value of the test statistic (round off to 2 decimal places). 2 , 3.95:75 056 22. Based on your answer to 19 and 21, what is your statistical decision? ries HoTS 23. Interpret your answer to 22. These is Surficient eidence that te ompe ot t peple hoit ben in car ocudemrs than dniking and driig 24. In English and the context of this scenario, what is the power? wwiie dniving in t 25. From your answers above, could you have made a type II error? Yes or No Explain your answer.Explanation / Answer
Answer to the question)
Proportion of texting = 58 /81
proportion of drinking = 23 /81
.
Answer # 14)
Question fo itnerest is: Does texting cause more accidents as compared to driving?"
Answer# 15) The test situation is that we assume that proporiton of accidents due to texting must be equal to proporiton of accidents due to Drinking , or in other words we expect the proportion of accidents due to texting to be 0.50 , but the claim is that the proportion of accidents due to texting is greater than 0.50
Thus it is a question of one sample , where the parameter is question is Population proportion P
.
Answer# 16)
Population Proportion ( P) = 0.50 ..[we assume it to be equal to that of driving]
.
Answer # 17)
Sample proportion is obtained by the sample data
out of 81 acidents studies, 58 were due to texting
thus sample proportion (P^) = 58 /81 = 0.7160
.
Answer # 18)
Alternate Hypothesis: The population proportion of the accidents due to texting is greater than 0.50. This implies more accidents are caused due to texting
Ha: P > 0.50
.
Answer #19)
Since the alternate hypothesis is has the symbol " > " , this implies it is a right tailed test
Thus for 5% significance level , the critical value of Z is +1.645
.
Answer # 20)
The Null Hypothesis would be rejected for all Z values that are greater than 1.645
Rejection region: Z > +1.465
.
Answer # 21)
Formula of Test Statistic is:
Z = (P^ - P) / sqrt(P * (1-P) / n)
on plugging the values we get
Z = (0.7160 - 0.5000) / sqrt(0.5 *0.5 /81)
Z = 3.888
.
Answer #22)
Since we got Z statistic 3.888 > Z critical +1.645 , we REJECT the Null Hypothesis
.
Answer # 23)
Since we reject the Null , this implies that there is strong evidence to support the claim that texting is more dangerous as compared to drinking , as it causes more accidents
.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.