The International Air Transport Association surveys business travelers to develo

Question

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airports. The maximum possible rating is 10. Suppose a simple random sample of 50 business travelers is selected and each traveler is asked to provide a rating for the Miami International Airport. The ratings obtained from the sample of 50 business travelers follow.

Develop a 95% confidence interval estimate of the population mean rating for Miami. Round your answers to two decimal places.

Enter your answer using parentheses and a comma, in the form (n1,n2). Do not use commas in your numerical answer (i.e. use 1200 instead of 1,200, etc.)

1 5 6 7 8 8 8 9 9 9 9 10 3 4 5 5 7 6 8 9 10 5 4 6 5 7 3 1 9 8 8 9 9 10 7 6 4 8 10 2 5 1 8 6 9 6 8 8 10 10

Explanation / Answer

From the given data we have

standard error = std. dev. / sqrt(n) = 2.55/sqrt(50) = 0.3606

For 95% confidence limit, z-score value is +/-1.96

Lower limit = mean - z*SE = 6.76 - 1.96*0.3606 = 6.0533

Upper limit = mean + z*SE = 6.76 + 1.96*0.3606 = 7.4667

mean 6.76 std. dev. 2.5519 n 50

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