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The International Air Transport Association surveys business travelers to develo

ID: 3376464 • Letter: T

Question

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airports. The maximum possible rating is 10. Suppose a simple random sample of 50 business travelers is selected and each traveler is asked to provide a rating for the Miami International Airport. The ratings obtained from the sample of 50 business travelers follow. 3 7 8 9 10 10 10 9 9 9 9 8 5 6 7 7 9 8 10 9 8 7 6 8 7 9 5 3 9 10 10 9 9 8 9 8 6 10 8 4 7 3 10 8 9 8 10 10 8 8 Develop a 95% confidence interval estimate of the population mean rating for Miami. Round your answers to two decimal places.

Explanation / Answer

Solution : Given data 3 7 8 9 10 10 10 9 9 9 9 8 5 6 7 7 9 8 10 9 8 7 6 8 7 9 5 3 9 10 10 9 9 8 9 8 6 10 8 4 7 3 10 8 9 8 10 10 8 8

=> n = 50

=> mean x = sum of the terms/number of the terms = 396/50 = 7.92

=> standard deviation ? = 1.9149

For 95% confidence interval , Z = 1.96

=> The 95% confidence interval for the population mean is x +/- Z*?/sqrt(n)

=> 7.92 +/- 1.96*1.9149/sqrt(50)

=> (7.39 , 8.45) rounded

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