18&flushed-false;&cld; 481 t C , Rre? Statistics-Math 146-NSC-Winter 2018 Homewo

Question

18&flushed-false;&cld; 481 t C , Rre? Statistics-Math 146-NSC-Winter 2018 Homework: Chap 2, Section 5 Score: 0.57 of 1 pt 19 of 19(19 complete) HW Score: 2.5.48 The life spans of a species of fruit fly have a bell-shaped distribution, with a mean of 35 days and a standard deviation of 4 days a) The life spans of three randomly selected fruit fies are 37 days, 31 days, and 47 days Find thascore that come prds to each ite span Delemi·when ay of I (b) The Ife spans of three randomly solocted fruit fhes are 43 days, 27 days, and 31 days Using the Empirical Rule, find the percentie that coresponds to ach lie sean. (a) The z-score corrasponding a life span of 37 days is 0.5 Type an integer or a decimal rounded to two decimal places as needed.) The z-score corresponding a life span of 31 days is -1 (Type an integer or a decimal rounded to two decimal places as needed.) The z-soore corresponding a life span of 47 days is 3 Type an integer or a decimal rounded to two decimal places as needed ) Select all of the life spans that are unusual. A. 31 days B. 47 dayt C 37 days D None of the lfe spans are unusual. (b) Dotermine the percentiles using the Empirical Rule. Enter your answer in the edit flelds and then click Check Answer Clear All All parts showing MacBook Air

Explanation / Answer

All answers of part (a) are correct.

Part (b).

By empirical rule, the percentile for z scores are

Mean is 35 days and standard deviation is 4 days.

43 day -

z = (43 - 35) / 4 = 8/4 = 2

So, the percentile for 43 day is 97.5

27 day -

z = (27 - 35) / 4 = -8/4 = -2

So, the percentile for 27 day is 2.5

31 day -

z = (31 - 35) / 4 = -4/4 = -1

So, the percentile for 27 day is 16

z score Approximate percentile -2 2.5th -1 16th 0 50th 1 84th 2 97.5th

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