o he esults support he be that 0.9% of newborn babi A random sample o 853 brths
ID: 3356865 • Letter: O
Question
o he esults support he be that 0.9% of newborn babi A random sample o 853 brths included 433 boys. Use a 0.01 signi cance level to test he claim that 50.9% of newborn babies are boys Kound to two decimai places as neeaea.) are o Identify the P-value for this hypothesis test. The P-value for this hypothesis test is Round to three decimal places as needed.) ldentify the conclusion for this hypothesis test O A. Fail to reject Ho There is sufficient evidence to warrant rejection of the claim that 50 9% of newborn babies are boys. O B. Fail to reject Ho. There is not sufficient evidence to warrant rejection of the claim that 50.9% of newborn babies are boys. O c. Reject Ho There is sufficient evidence to warrant rejection of the claim that 50 9% of newborn babies are boys. O D. Reject Ho There is not sufficient evidence to warrant rejection of the claim that 50.9% of newborn babies are boys. Do the results support the belief that 50.9% of newborn babies are boys? O A The results support the belief that 50.9% of newborn babies are boys because there was no evidence to show that the belie is untrue. O B. The results do not support the belief that 50 9% of newborn babies are boys because there was sufficient evidence to show that the belief is untrue ° C. The results support the belief that 50.9% of newborn babies are boys because there was sufficient evidence to show that the belief is true D The results do not support the belief that 50.9% of newborn babies are boys. the results mere how that there is not strong evidence against the rate of 509Explanation / Answer
The statistical software output for this problem is:
One sample proportion summary hypothesis test:
p : Proportion of successes
H0 : p = 0.509
HA : p 0.509
Hypothesis test results:
Hence,
Null and Alternative Hypotheses: Option B is correct.
Test statistic = -0.08
P - value = 0.936
Conclusion: Option B is correct.
Do the result support the belief: Option A is correct.
Proportion Count Total Sample Prop. Std. Err. Z-Stat P-value p 433 853 0.50762016 0.0171169 -0.080612485 0.9358Related Questions
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