Need the answers for 1.2,1.3 and 1.4. The following numbers of defectives are co

Question

Need the answers for 1.2,1.3 and 1.4.

The following numbers of defectives are collected from each day's production. Total production for each day is 300 pieces. Disregard the fact that there are too few subgroups to construct a valid control chart. (4 x 2 = 8 points) DATASHEET Proportion Non Conforming Number # Defective or Day InspectedDefects 300 300 300 300 300 300 300 300 300 300 20 0.07 0.11 0.14 0.08 0.07 0.22 0.11 0.03 0.07 0.10 43 24 6S 32 20 31 10 1.3 Assuming that the data from this problem are defects, rather than defectives, What would be the C Chart control limits for number of defects day? UCL,-46.4 1.1 Calculate control limits for a P chart (Reference answer: UCL-0.152 300 10 SumNp- Sumn = Pbar UCLp 300 1.00 0.10 0.152 LCLp0.048038476 Cba UCL,- LCL 1.2 Convert the control limits for the problem 1.1 into Np control chart limits (Reference Answer: UCLnp = 45.6) 1.4 Discard out of control subgroups and determine revised control limits for problem 1.1 300 300 SumNpdiscarded SumNdiscarded Pbar UCL:p LCLt Pbar- Pbancw- UCLpnew

Explanation / Answer

Question 1.2

Here p- bar = 0.10

npbar = 0.10 * 300 = 30

UCLnp = 30 + 3 * sqrt[0.10 * 0.90 * 300] = 30 + 15.6 = 45.6

LCLnp = 30 - 3 * sqrt [ 0.10 * 0.90 * 300] = 30 - 15.6 = 14.4

QUestion 1.3

g = 10

Cbar = 30

UCLc = 30 + 3 * sqrt (30) = 30 + 16.43 = 46.43 (as given)

LCLc = 30 - 3 * sqrt (30) = 30 - 16.43 = 13.57

Question 1.4

Here we can discard day 6 and day 8 samples.

Sum (Np discarded) = (65 + 10) = 75

Sum (N discarded) = 300 + 300 = 600

pbar = 225/(8 * 300) = 0.09375

UCLpnew = p- bar + 3 * sqrt [p * (1-p)/N] = 0.09375 + 3 * sqrt [ 0.09375 * 0.90625 /300]

= 0.09375 + 3 * 0.01683 = 0.1442

LCLpnew = p-bar - 3 * sqrt [p * (1-p)/N] = 0.09375 - 3 * sqrt [ 0.09375 * 0.90625 /300]

= 0.09375 - 3 * 0.01683 = 0.0433

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