This paper will test your abilities to write an argumentative paper about a cont
ID: 3357982 • Letter: T
Question
This paper will test your abilities to write an argumentative paper about a controversial topic in a way that fairly considers both sides of the issue. Use the concepts of Rogerian Argument-try to acknowledge the good points of the opposition and, if possible, establish common ground. Topic On July2,2017,President Trump tweeted the following My use of social media is not Presidentialit's MODERN DAY PRESIDENTIAL Make America Great Again! This followed criticism of his use of Twitter to speak directly to his followers and bypass the usual means (he would say "constraints' of addressing the public through the media. Research this controversy. Why do people object to his use of Twitter? What has been the norm in the past for the way presidents address the American people? What are the requirements for archiving statements by the President, and what are the problems, then, when those statements are made via a communication platform that allows the President to delete his statements? After you research the issue, you will write a paper about whether or not you believe a president should use Twitter. You are not wrting an argument about whether President Trump should use Twiter, but rather whether any president should use Twitter. You will need to include in-text citations and a Works Cited page (which does not count as one of your pages for length). Consult the MLA section in your Handbook. Details: You must use at least two reputable sources.Anything you state as a fact (such as "Young people don't use Twitter) must be supported by evidence. Your paper must be 4-5 pages in length, double-spaced in a Times New Roman 12 font. Your paper must be subnaited toExplanation / Answer
We are allowed to do 1 question at a time. Post again for second question.
Last: aircraft
Let A be the event a seam fails.
Let B be the event a rivet fails.
a) P[A] = 1 - P[B']^22
0.23 = 1 - P[B']^22
0.77 = P[B']^22
P[B'] = 0.77^(1/22)
P[B'] = 0.988
P[B] = 1 - P[B'] = 0.012
b)
0.09 = 1 - P[B']^22
P[B']^22 = 0.91
P[B'] = 0.996
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