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1) 51 samples were analyzed, and the sample mean was 9.7 ounces. Can you determi

ID: 3358351 • Letter: 1

Question

1) 51 samples were analyzed, and the sample mean was 9.7 ounces. Can you determine the standard deviation of the sample?

D) 0.017

2) How do we interpret the p-value for this test?

There is only a 0.034% chance that this sample mean would be observed if the pharmacists are following regulations.

3) The pharmacist wants to create a 95% confidence interval to estimate the true average penicillin dosage being dispensed by her team. Fill in the pieces below:

t critical =    

margin of error =    (report to 3 decimal places)

low estimate =    (report to 2 decimal places)

high estimate =    (report to 2 decimal places)

4) What conclusion should the pharmacist reach about the volume of penicillin being dispersed by her team?

A) 0.500 10.2 ounces

Explanation / Answer

1)here std error of mean =(X-mean)/t =(9.7-10.2)/(-5.89)=0.0849

therefore std deviaiton =std error*(n)1/2 =0.0849*(51)1/2 =0.606

option C is correct

2)option D is correct

3) t critical =2.0086

margin of error =t*std error =0.171

lower estimate =sample mean -margin of errror =9.53

highestimate =sample mean +margin of errror =9.87

4)

C) The pharmacists are not dispersing the required amount of penicillin.