1) 50 litres of a gas at 0 degrees celsuis are heated to 127degrees celsuis. Wha
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1) 50 litres of a gas at 0 degrees celsuis are heated to 127degrees celsuis. What is the final volume? The pressure remainsconstant. 2) calculate the density of CO2 gas at STP (in g/l) 3) A cylinder in a gasole engine initially has a volume of0.50L and contains gases that exert a pressure of 101.3 kPa. Whatis the pressure of the gases when the volume of the cylinder isreduce to 0.20L and there is no change in the amount or temperatureof the gaseous mixture? 1) 50 litres of a gas at 0 degrees celsuis are heated to 127degrees celsuis. What is the final volume? The pressure remainsconstant. 2) calculate the density of CO2 gas at STP (in g/l) 3) A cylinder in a gasole engine initially has a volume of0.50L and contains gases that exert a pressure of 101.3 kPa. Whatis the pressure of the gases when the volume of the cylinder isreduce to 0.20L and there is no change in the amount or temperatureof the gaseous mixture?Explanation / Answer
50 litres of a gas at 0 degrees celsuis are heated to 127 degreescelsuis. What is the final volume? The pressure remainsconstant. V1T1=V2T250Lits x 273 K = V2X400K==> V2=34.125 Lits 2) calculate the density of CO2 gas at STP (in g/l) AT STP 1 MOLE OF GAS OCCUPIES22.414 Lit 44 g of CO2 GAS OCCUPIES 22.414 Lit then density = m/v = 44g/22.414 Lit=1.9630g/l 3)A cylinder in a gasole engine initially has avolume of 0.50L and contains gases that exert a pressure of 101.3kPa. What is the pressure of the gases when the volume of thecylinder is reduce to 0.20L and there is no change in the amount ortemperature of the gaseous mixture? P1V1=P2V2 101.3 kPa =1atm so, 1 atm X 0.50L =P2 X 0.20L ==>P2=[1 atm X 0.50L] / 0.20L = 2.5 atms
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