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QUESTION 1 A certain binomial experiment consists of 100 independent Bernoulli t

ID: 3359182 • Letter: Q

Question

QUESTION 1

A certain binomial experiment consists of 100 independent Bernoulli trials with the probability of success is 0.55. X is the random variable which counts the successes. Determine the following probabilities:

0.1346, 0.8654, 0.8151

0.1346, 0.8172, 0.8638

0.1346, 0.8172, 0.8151

0.1827, 0.8172, 0.8151

0.75 points   

QUESTION 2

The density function of a continuous random variable X is given by

Find the expected value of X.

E[X] = x

E[X] = 1.5

E[X] = 0

E[X] = 1

0.75 points   

QUESTION 3

A six-sided fair die is rolled once. Let X be the random variable that assigns the value of the outcome (i.e., X(w) = 1 means that the outcome was a 1, etc.) What is the expected value, E(X)?

1

7/2

3

1/6

0.75 points   

QUESTION 4

Which of the following statements are not correct?

The study of continuous random variables requires the continuous mathematics of the calculus - integrals and derivatives.

In general, each outcome of an experiment can be associated with a number by specifying a rule of association.

The number of movies you watched last year is an example of a continuous random variable.

To study basic properties of discrete random variables, only the tools of discrete mathematics -summation and differences - are required.

0.75 points   

QUESTION 5

A fair coin is tossed 5 times. What is the probability of a run of 3 Heads (i.e., an outcome contains 3 Heads in succession, but not 4 or 5).

1/32

5/32

10/32

3/32

0.75 points   

QUESTION 6

The lifetime of certain type of light bulbs is exponentially distributed with an average of 1000 hours. What is the probability that a given light bulb will last more 900 hours?

0.5934

0.6321

0.4066

0.3679

0.75 points   

QUESTION 7

A random variable X has gamma distribution with parameters alpha = 2 and beta = 3. Find P(6< x < 12 ).

0.017

0.500

0.983

0.314

0.75 points   

QUESTION 8

A random variable X has gamma distribution with parameters alpha = 2 and beta = 3. Find P(x < 6 ).

0.577

0.801

0.594

0.983

0.75 points   

QUESTION 9

A random variable X has gamma distribution with parameters alpha = 2 and beta = 3. Find P(x > 9).

0.677

0.199

0.801

0.323

0.75 points   

QUESTION 10

Which of the following is (are) conditions of a binomial experiment?

There is a sequence of n trials, where n is fixed in advance of the experiment.

The trials are identical, and each trial can result in one of the same two possible outcomes, which we denote by success (S) or failure (F).

The trials are independent, so that the outcome of any particular trial does not influence the outcome of any other trial.

The probability of success is the same (constant) from trial to trial; we denote this probability by p.

All of the above are conditions of a binomial experiment.

0.75 points   

QUESTION 11

The probability density function of a random variable X is given by f(x) = 1 for 0 <= x <= 1 and 0 elsewhere. Then P(X = 0.25) =

0

0.00001

0.5

0.25

0.75 points   

QUESTION 12

A random number generator in a CAS produces pseudo-random numbers which are uniformly distributed in any given interval. Suppose that the generator is asked to produce 10,000 numbers between 20 and 25. About how many numbers do you expect to get greater than 24? (Assume continuity).

1000

2500

200

2000

0.75 points   

QUESTION 13

The number of gallons of gasoline sold daily by a gas station is approximately uniformly distributed between 4000 and 4200 gallons. The profit in dollars is given by the function f(x) = 0.45x - 480 where x is the number of gallons sold. What is the expected profit per day?

$1845

$4100

$480

$1365

0.75 points   

QUESTION 14

Let X be a discrete random variable with probability distribution

The variance and the standard deviation of X are

V(X) = 1.02,   SD(X) = 1.05

V(X) = -1.05,   SD(X) = 1.02

V(X) = 1.05,   SD(X) = 1.02

V(X) = -1.02,   SD(X) = -1.05

0.75 points   

QUESTION 15

Let X be a discrete random variable with E(X) = 0 and V(X) = 1. Find E(20X + 100) and V(20X + 100).

E(20X + 100) = 100,    V(20X + 100) = 500

E(20X + 100) = 100,    V(20X + 100) = 400

E(20X + 100) = 0,    V(20X + 100) = 400

E(20X + 100) = 0,    V(20X + 100) = 0

0.75 points   

QUESTION 16

Forty percent of the students taking Statistics 101 this semester bought a new book while the remaining 60% either bought a used book already had one. If four students taking Statistics 101 are selected at random, what is the probability that exactly two bought new books?

0.50

0.5248

0.3456

0.8208

0.75 points   

QUESTION 17

A company sells three different types of 2 GB USB's at different prices depending on the make, type, and other characteristics. Brand A sells for $12.00, brand B for $25.00, and brand C for $40.00. Of these USB's sold, 65% are brand A, 25% are brand B, and 10% are brand C. The profit for the company is 40% of the retail value, so Y = 0.4X is the rv for the profit. Find the expected value and the variance for the profit.

E(Y) = $4.74,     V(Y) = $22.47

E(Y) = $11.86,     V(Y) = $269.23

E(Y) = 11.86,     V(Y) = $6.55

E(Y) =$7.22,     V(Y) = $13.45

0.75 points   

QUESTION 18

The function p assumes the following values:

What value must p assume at x = 3 for p to be a probability distribution?

Any positive value.

Any value between 0 and 1.

0

0.12

0.75 points   

QUESTION 19

A random variable X has the following cumulative distribution function:

                0            for x < 0
                0.2        for 0 <= x < 1
  F(x) =   { 0.5         for 1 <= x < 2
               0.9         for  2 <= x < 4
                1            for  4 <= x

The probability distribution of X is

0.75 points   

QUESTION 20

A random variable X has binomial distribution with parameters n = 75 and p = 0.75. Find the expected value and the variance of X.

E(X) = 18.75, V(X) = 3.75

E(X) = 18.75, V(X) = 14.0625

E(X) = 56.25, V(X) = 14.0625

E(X) = 56.25, V(X) = 3.75

a.

0.1346, 0.8654, 0.8151

b.

0.1346, 0.8172, 0.8638

c.

0.1346, 0.8172, 0.8151

d.

0.1827, 0.8172, 0.8151

Explanation / Answer

Ans:

3)

E(X)=1*(1/6)+2*(1/6)+3*(1/6)+4*(1/6)+5*(1/6)+6*(1/6)=(1/6)*(1+2+3+4+5+6)=21/6=7/2

Option b is correct.

5)

P(x=3)=5C3*(1/2)3*(1/2)2=10*(1/32)=10/32

Option C is correct.

6)

P(X>900)=e-(900/1000)=e-0.9=0.4066

Option C is correct.

10)

Option E is correct.(all conditions are required for  binomial distribution)

20)

E(X)=75*0.75=56.25

Var(X)=75*0.75*0.25=14.0625

Option C is correct.

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