To help consumers assess the risks they are taking, the Food and Drug Administra

Question

To help consumers assess the risks they are taking, the Food and Drug Administration (FDA) publishes the amount of nicotine found in all commercial brands of cigarettes. A new cigarette has recently been marketed. The FDA tests on this cigarette yielded mean nicotine content of 24.9 milligrams and standard deviation of 2.3 milligrams for a sample of n-9 cigarettes. Construct a 95% confidence interval for he mean nicotine content of ti brand of e ae e OA, 24.9±1.839 B. C. OD, 24.9±1.768 24.9±1.734 24.9±1.875

Explanation / Answer

Solution:- option B.  24.9 +/-  1.768

Given that mean 24.9,sd = 2.3,n = 9 , t = 2.306

=> 24.9 +/- 2.306*(2.3/sqrt9)

= 24.9 +/-  1.7679

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