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If a keyboard operator averages 2 errors per page of newsprint and if these erro

ID: 3359579 • Letter: I

Question

If a keyboard operator averages 2 errors per page of newsprint and if these errors follow a Poisson process, what is the probability that at least 5 errors will be found on a given page? If a keyboard operator averages 2 errors per page of newsprint and if these errors follow a Poisson process, what is the probability that at least 5 errors will be found on a given page? If a keyboard operator averages 2 errors per page of newsprint and if these errors follow a Poisson process, what is the probability that at least 5 errors will be found on a given page?

Explanation / Answer

Mean = 2 errors per page

P(X = x) = e-2 * 2x / x!

P(X > 5) = 1 - (P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4))

= 1 - (e-2 * 20 / 0! + e-2 * 21 / 1! + e-2 * 22 / 2! + e-2 * 23 / 3! + e-2 * 24 / 4!)

= 1 - 0.947

= 0.053

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