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QUESTION 3 Suppose that the time in hours that student Bob Webb spends on the in

ID: 3361412 • Letter: Q

Question

QUESTION 3 Suppose that the time in hours that student Bob Webb spends on the internet every day is gamma distributed with parameters alpha = 3 and beta = 2. What is the probability that he spends between 2 and 4 hours on a given day? a. 0.045 b. 0.149 c. 0.383 d. 0.243

QUESTION 7

Let A and B be any two events with positive probability. Which of the following statements is always true?

P(A|B) + P(A|B') = 1

P(A|B) + P(A'|B) = 1

P(A|B) + P(A|B') = 1

P(A|B) = 1 - P(A'|B')

For the following set of data find the sample mean, the sample median, and the sample variance.  

54, 44, 59, 43, 51, 54, 58, 53, 50, 47, 51, 44, 55, 45, 46, 62, 62, 55, 53, 49

51.75, 52, 5.83

51.75, 52, 33.99

52, 51.75, 33.99

51.75, 5.83, 33.99

QUESTION 15

A random variable X has cumulative distribution function

Find the density function of F.

f(x) = 6x(1 + x) for 0 <= x <= 1, f(x) = 0 elsewhere

f(x) = 3x(1 + x) for 0 <= x <= 1, f(x) = 0 elsewhere

f(x) = x(1 - x) for 0 <= x <= 1, f(x) = 0 elsewhere

f(x) = 12x(x-1)2 for 0 <= x <= 1, f(x) = 0 elsewhere

QUESTION 13

Let X be normally distributed with mean 10 and standard deviation 2. Then approximately 68% of the area under this normal curve centered about the mean fall between which two values?

x = -.47, x = .47

x = 9, x = 11

x = 0, x = 10.9

x = 8, x = 12

x = 9.1, x = 10.9

a.

P(A|B) + P(A|B') = 1

b.

P(A|B) + P(A'|B) = 1

c.

P(A|B) + P(A|B') = 1

d.

P(A|B) = 1 - P(A'|B')

For the following set of data find the sample mean, the sample median, and the sample variance.  

54, 44, 59, 43, 51, 54, 58, 53, 50, 47, 51, 44, 55, 45, 46, 62, 62, 55, 53, 49

a.

51.75, 52, 5.83

b.

51.75, 52, 33.99

c.

52, 51.75, 33.99

d.

51.75, 5.83, 33.99

QUESTION 15

A random variable X has cumulative distribution function

Find the density function of F.

a.

f(x) = 6x(1 + x) for 0 <= x <= 1, f(x) = 0 elsewhere

b.

f(x) = 3x(1 + x) for 0 <= x <= 1, f(x) = 0 elsewhere

c.

f(x) = x(1 - x) for 0 <= x <= 1, f(x) = 0 elsewhere

d.

f(x) = 12x(x-1)2 for 0 <= x <= 1, f(x) = 0 elsewhere

QUESTION 13

Let X be normally distributed with mean 10 and standard deviation 2. Then approximately 68% of the area under this normal curve centered about the mean fall between which two values?

a.

x = -.47, x = .47

b.

x = 9, x = 11

c.

x = 0, x = 10.9

d.

x = 8, x = 12

e.

x = 9.1, x = 10.9

Explanation / Answer

7)

P(A|B) + P(A'|B) = 1 is correct

8)

from above mean=51.75 ; median=(n+1)/2 th value =52 and sample variance =33.99

hence option

51.75, 52, 33.99

15) for this picture not attached please revert with expression ; i will update

13) as 68% values fall 1st std deviation from mean

x = 8, x = 12

b.

P(A|B) + P(A'|B) = 1 is correct

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