In an experiment to learn if substance M can help restore memory, the brains of

Question

In an experiment to learn if substance M can help restore memory, the brains of 24 rats were treated to damage their memories. The rats were trained to run a maze. After a day, 12 rats were given M, and six of them succeeded in the maze; only three of the 12 control rats were successful. The z test for "no difference" against "a higher proportion of the M group succeeds" has what values for the z-statistic and P-value? (Round your z-value to two decimal places and your P-value to three decimal places.)

Explanation / Answer

Given that,
sample one, x1 =6, n1 =12, p1= x1/n1=0.5
sample two, x2 =3, n2 =12, p2= x2/n2=0.25
null, Ho: p1 = p2
alternate, H1: p1 > p2
level of significance, = 0.025
from standard normal table,right tailed z /2 =1.96
since our test is right-tailed
reject Ho, if zo > 1.96
we use test statistic (z) = (p1-p2)/(p^q^(1/n1+1/n2))
zo =(0.5-0.25)/sqrt((0.375*0.625(1/12+1/12))
zo =1.265
| zo | =1.265
ANSWERS
---------------
test statistic: 1.27
p-value: 0.103

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