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If you are not going to write the solution in minitab leave it to someone else =

ID: 3364324 • Letter: I

Question



If you are not going to write the solution in minitab leave it to someone else = V3(0.868)(0.132) ·3437 = 0.5863 e mean number of orders filled correctly in a sample of three orders is 2.604, and the d deviation is 0.5863. The probability that all three orders are filled correctly is 0.6540, %. The probability that none of the orders are filled correctly is 0.0023 (0.23%). The lity that at least two orders are filled correctly is 0.9524 (95.24%). 5.2 12A recent Pew Research survey reported that 48% of 18- to 29-year-olds in the United States own tablets. (Data extracted from Tablet and E-Reader Ownership,"bit.ly/1gEwogC). Using the binomial distribution, what is the probability that in the next 0)? six 18- to 29-year-olds surveyed a. four will own a tablet? b. all six will own a tablet? = 8)? 5)2 iation of the variable c. at least four will own a tablet? ons: d. What are the mean and standard deviation of the number of 18- to 29-year-olds who will own a tablet in a survey of six? What assumptions do you need to make in (a) through (c)? e. 5.13 A student is taking a multiple-choice exam in which cach question has four choices. Assume that the student has no knowl redge of the correct answers to any of the questions. She has de- h che will place four balls (marked

Explanation / Answer

12) n = 6

P = 0.48

A) P(x = 4) = 6C4 * (0.48)^4 * (0.52)^2 = 0.2153

B) P(x = 6) = 6C6 * (0.48)^6 * (0.52)^0 = 0.0122

C) P(X >4) = P (x = 4) + P (x = 5) + P (x = 6)

= 6C4 * (0.48)^4 * (0.52)^2 + 6C5 * (0.48)^5 * (0.52)^1 + 6C6 * (0.48)^6 * (0.52)^0

= 0.307

D) mean = n * P = 6 * 0.48 = 2.88

Standard deviation = sqrt (n * P * (1 - P))

= sqrt (6 * 0.48 * 0.52) = 1.224

E) The assumptions are

I) The sample consists of a fixed number of observations n = 8

Ii) The probability of the observations being classified as success P = 0.48 and failure (1 - P) = 0.52, are constant for all the observations.

III) The outcome (success or failure) of any observation is independent of the outcome of any other observations.

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