In a sample of 1100 U.S.? adults, 219 dine out at a resaurant more than once per

Question

In a sample of 1100 U.S.? adults, 219 dine out at a resaurant more than once per week. Two U.S. adults are selected at random from the population of all U.S. adults without replacement. Assuming the sample is representative of all U.S.? adults, complete parts? (a) through? (d). ?(a) Find the probability that both adults dine out more than once per week. The probability that both adults dine out more than once per week is nothing . ?(Round to three decimal places as? needed.) ?(b) Find the probability that neither adult dines out more than once per week. The probability that neither adult dines out more than once per week is nothing . ?(Round to three decimal places as? needed.) ?(c) Find the probability that at least one of the two adults dines out more than once per week. The probability that at least one of the two adults dines out more than once per week is nothing . ?(Round to three decimal places as? needed.) ?(d) Which of the events can be considered? unusual? Explain. Select all that apply. A. The event in part? (c) is unusual because its probability is less than or equal to 0.05. B. None of these events are unusual . C. The event in part left parenthesis a right parenthesis is unusual because its probability is less than or equal to 0.05 . D. The event in part? (b) is unusual because its probability is less than or equal to 0.05.

Explanation / Answer

a) probability that both adults dine out more than once per week=(219/1100)*(219/1100)=0.040

b) probability that neither adult dines out more than once per week=(1-219/1100)*(1-219/1100)=0.641

c)probability that at least one of the two adults dines out more than once per week =1-0.641=0.359

d)the event in part (A) is unusual because its probability is less than or equal to 0.05

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