Emmanuel Erimide & 1 6/30/18 10:44 PM Quiz: Quiz 2 Week 4 Time Remaining: 03 53

Question

Emmanuel Erimide & 1 6/30/18 10:44 PM Quiz: Quiz 2 Week 4 Time Remaining: 03 53 15 Submit Quiz This Question: 1 pt 8 of 17 (0 complete) This Quiz: 17 pts po and the probability that a carton has a puncture and has a smashed comer is 0.006. Answer parts (e) and (b) below comer" O A. No, a carton cannot have a puncture and a smashed comer O B. No, a carton can have a puncture and a smashed comer O C. Yes, a carton can have a puncture and a smashed corner O D. Yes, a carton cannot have a puncture and a smashed corner (b) If a quality inspector randomly selects a carton, find the probability that the carton has a puncture or has a smashed comer. (Type an integer or a decimal. Do not round )

Explanation / Answer

Solution

Let A and B respectively represent the events that the carton has a puncture and the carton has a smashed corner.

Then, the given data, in probability language, would translate as:

P(A) = 0.07 ……………………………………………………………………… (1)

P(B) = 0.09 ……………………………………………………………………… (2)

P(A ? B) = 0.006 ……………………………………………………………… (3)

Back-up Theory

For 2 events, A and B,

P(A ? B) = P(A) + P(B) - P(A ? B), in general and ……………………………(4)

If A and B are mutually exclusive, P(A ? B) = 0 ……………………………….(5)

Now, to work out the answer,

Part (a)

(3) and (5) => A and B are mutually exclusive. So, option C ANSWER

Part (b)

Probability the carton has a puncture or the carton has a smashed corner

= P(A ? B)

= 0.07 + 0.09 – 0.006 [vide (4)]

= 0.154 ANSWER -weight:normal'>0.8 ANSWER

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