Lab- Answer the follwoing questions- part2- Welcome to Minitab, press F1 for hel

Question

Lab- Answer the follwoing questions- part2-

Welcome to Minitab, press F1 for help. Expected counter are printed below observed counts Chi-Square contributions are printed below expected counts Chi- Square Test: Photographer, Reporter, Banker Expected counts are printed below observed counts Chi-Square contributions are printed below expected counts Find the P-value for Your Hypothesis Test:: Select STAT rightarrow TABLES rightarrow CHI-SQUARE TEST (TWO-WAY TABLE IN WORKSHEET). Select C1 and C2 for Columns containing the table Click OK. Compare p-value to alpha to make a conclusion.. Explain your conclusion in coutext. Use the data provided in the table below to test (at the 10% level of significance) if a person's favorite superhero is dependent on their occupation. Label column C3 Photographer, column C4 Reporter and column C5 Banker: Enter the observed frequencies in the table below into the appropriate cells in Row 1, Row 2. and Row 3 in Minitab. You should end up with a 3 times 3 matrix. Use the formula Expected Count = Row total X Column Total/ n to fill in the expected matrix for the contingency table. Note: You will not need to enter these in Minitab This step is just to practice calculating expected cell counts. Find the P-value for Your Hypothesis Test: Select STAT rightarrow TABLES rightarrow CHI-SQUARE TEST (TWO-WAY TABLE IN WORKSHEET). Select C3, C4. and C5 for Columns containing the table. Click OK. Compare p-value to alpha to make a conclusion. Explain your conclusion in context. In general, are chi-square distributions normal, right skewed, or left skewed? How do you calculate the expected frequencies for the expected matrix? As the differences between the observed frequency and the expected frequency increase, does the value of the chi-square test statistic increase, or decrease? For tests of independence, what are we comparing to see if the difference is too large to be due to chance alone?

Explanation / Answer

H0: A person's superhero is independent of their occupation.

H1: A person's superhero is not independent of their occupation.

The expected matrix is

p-value = 0.002

Since p-value = 0.002 < alpha = 0.10, we reject H0 and conclude that a person's superhero is not independent of their occupation.

1. In general chi-square distributions are right (positively) skewed.

2. The expected frequency is calculated as (row total x column total)/(total number of observations)

3. The value of chi-square test statistics increases as the difference between the observed and expected frequency increases.

4. We are comparing the observed and expected frequency.

Photographer Reporter Banker Spiderman 38.83 37.79 27.39 Batman 32.48 31.61 22.91 Superman 40.69 39.60 28.70

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