Need help coding this problem in Matlab. Here is the question along with the cor

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Need help coding this problem in Matlab. Here is the question along with the correct answer.

For the position shown where theta = 30degree, point A on the sliding collar has a constant velocity v = 0.3 m/s with corresponding lengthening of the hydraulic cylinder AC. For this same position BD is horizontal and DE is vertical. Determine the angular acceleration alphaDE of DE at this instant. VD = VE + omegaDE Times rD/E = O + omegaDEK Times (0.09 j) Vo = -0.09omegaDE i m.s From and comparing i and j of Vo omegaDE = -0.1022/0.09 = -1.125 rod.s omegaBD = 0.0585/0.148 ab = ac Times rB/c -omega2BC rB.C = O as aB = -0.1973 i - 0.0379 j m/s2 comparing i = -0.220/-0.09 = 2.45 rod/s2

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