Without changing the source code, use gdb get the program to spit out My name is

Question

Without changing the source code, use gdb

get the program to spit out My name is l33tn00b

Big thumbs up if you got it

#include <iostream>

#include <cstdlib>

#include <cstring>

// "carefully chosen to have 8 bytes so you can just fit it in there"
// l33tn00b

using namespace std;

int main(int argc, char* argv[]){

long* ptr = new long;

long value = 15;

char user[20];

char dev[] = "Andy";

strncpy(user, argv[1], strlen(argv[1]));

*ptr = value;

cout << "My name is " << dev << endl;

cout << "Your name is " << user << endl;

cout << "The pointer has value " << *ptr << endl;

return 0;

}

Explanation / Answer

Hi,
Though using gdb, you can still rely on the defined functions to pritnt your output, so if you want to print a given string by gdb, you can simply use,
where string can have your desired o/p which is l33tn00b in this case
(gdb) printf "%s ", string
Thumbs up if this was helpful, otherwise let me know in comments

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