Change the following C++ code to C code #include <iostream> using std::cout; #in

Question

Change the following C++ code to C code
#include <iostream>
using std::cout;
#include <iomanip> using std::setw;
#include <cmath>
bool prime( int n );
int main() { int count = 0;
cout << "The prime numbers from 1 to 10000are: ";
for ( int j = 2; j <= 10000; ++j ) if ( prime( j ) ) { ++count; cout << setw( 5 ) << j;
if ( count % 10 == 0 ) cout << ' '; }
return 0; }
bool prime( int n ) { for ( int i = 2; i <= static_cast< int > (sqrt( n ) ); ++i ) if ( n % i == 0 ) return false;
return true; } Change the following C++ code to C code
#include <iostream>
using std::cout;
#include <iomanip> using std::setw;
#include <cmath>
bool prime( int n );
int main() { int count = 0;
cout << "The prime numbers from 1 to 10000are: ";
for ( int j = 2; j <= 10000; ++j ) if ( prime( j ) ) { ++count; cout << setw( 5 ) << j;
if ( count % 10 == 0 ) cout << ' '; }
return 0; }
bool prime( int n ) { for ( int i = 2; i <= static_cast< int > (sqrt( n ) ); ++i ) if ( n % i == 0 ) return false;
return true; }

Explanation / Answer

//This programme will print all the number between 1 to 10000that are prime. void main() {   printf("The prime numbers from 1 to 10000are: "); for ( int j = 1; j <= 10000; j++ ) {    int flag=0; for(int i=2;i<j;i++) {    if(j%i==0)    flag++; } if(flag==0)    printf("%d",j); } return 0; }

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