Hello, I was just wondering, is it possible to lose data when usingpointers? I w

Question

Hello,
I was just wondering, is it possible to lose data when usingpointers?
I was using a value returning function with this header:
int *Mode(int *, int*)
basically, what happened is this.
I had the function return an array with the following numbers= {8,19,21,37,40}
Now, the problem is when I print it out from my main int( )the numbers changed, it became different.
The array showed the value = {8,1,0,7,3}
Not sure if this makes sense =/
Is it memory allocation issues? right now we're learningsomething called dynamic allocations...

I was just wondering, is it possible to lose data when usingpointers?
I was using a value returning function with this header:
int *Mode(int *, int*)
basically, what happened is this.
I had the function return an array with the following numbers= {8,19,21,37,40}
Now, the problem is when I print it out from my main int( )the numbers changed, it became different.
The array showed the value = {8,1,0,7,3}
Not sure if this makes sense =/
Is it memory allocation issues? right now we're learningsomething called dynamic allocations...

Explanation / Answer

#include<stdio.h> #define MAX_SIZE 1000 int main() {       int* arr;    int i;       //Calloc intializes all values to 0    //and the 5 represents the size.    arr = calloc(5,sizeof(int*));       arr[0] = 1;    arr[1] = 9;    arr[2] = 10;    arr[3] = 11;    arr[4] = 19;       for(i = 0; i < 5; i++)    printf("%d ",arr[i]);       system("pause");    return 0; }
#include<stdio.h> #define MAX_SIZE 1000 int main() {       int* arr;    int i;       //Calloc intializes all values to 0    //and the 5 represents the size.    arr = calloc(5,sizeof(int*));       arr[0] = 1;    arr[1] = 9;    arr[2] = 10;    arr[3] = 11;    arr[4] = 19;       for(i = 0; i < 5; i++)    printf("%d ",arr[i]);       system("pause");    return 0; }

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