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ID: 3622373 • Letter: L
Question
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http://joeparis.squarespace.com/storage/data_files/cs271/cs271_final_programming_exam_fall_2010.pdf
Part 2 only
In this problem, you’ll re-create the classic race of the tortoise and the hare. You’ll use random-number generation to develop a simulation of this memorable event. Our contenders begin the race at square 1 of 70 squares. Each square represents a possible position along the race course. The finish line is at square 70. The first contender to reach or pass square 70 is rewarded with a pail of fresh carrots and lettuce. The course weaves its way up the side of a slippery mountain, so occasionally the contenders lose ground. A clock ticks once per second. With each tick of the clock, your application should adjust the position of the animals according to the rules in the table below. Use variables to keep track of the positions of the animals (i.e., position numbers are 1–70). Start each animal at position 1 (the “starting gate”). If an animal slips left before square 1, move it back to square 1.
Animal Move type Percentage of the time Actual move
Tortoise Fast plod 50% 3 squares to the right
Slip 20% 6 squares to the left
Slow plod 30% 1 square to the right
Hare Sleep 20% No move at all
Big hop 20% 9 squares to the right
Big slip 10% 12 squares to the left
Small hop 30% 1 square to the right
Small slip 20% 2 squares to the left
Generate the percentages in the table by producing a random integer i in the range 1 =i =10. For the tortoise, perform a “fast plod” when 1 = i = 5, a “slip” when 6 = i = 7 or a “slow plod” when 8 = i = 10. Use a similar technique to move the hare. Begin the race by displaying
ON YOUR MARK, GET SET
BANG !!!!!
AND THEY'RE OFF !!!!!
Then, for each tick of the clock (i.e., each repetition of a loop), display a 70-position line showing the letter T in the position of the tortoise and the letter H in the position of the hare. Occasionally, the contenders will land on the same square. In this case, the tortoise bites the hare, and your application should display OUCH!!! beginning at that position. All output positions other than the T, the H or the OUCH!!! (in case of a tie) should be blank.
After each line is displayed, test for whether either animal has reached or passed square 70. If so, display the winner and terminate the simulation. If the tortoise wins, display TORTOISE
WINS!!! YAY!!! If the hare wins, display Hare wins. Yuch. If both animals win on the same tick of the clock, you may want to favor the tortoise (the “underdog”), or you may want to display It's a tie. If neither animal wins, perform the loop again to simulate the next tick of the clock. When you are ready to run your application, assemble a group of fans to watch the race. You’ll be amazed at how involved your audience gets!
Explanation / Answer
#include <iostream>
#include <cstdlib>
#include <iomanip>
using namespace std;
void movetort(int*);
void movehare(int*);
void print(int*,int*);
int main()
{int finish=70,tort=1,hare=1,rtime=0;
srand(time(0));
cout<<"ON YOUR MARK, GET SET BANG !!!!! AND THEY'RE OFF !!!!! ";
do
{movehare(&hare);
movetort(&tort);
print(&tort,&hare);
rtime++;
}while(tort<finish&&hare<finish);
if(tort>hare )
cout<<" TORTOISE WINS!!! YAY!!! ";
else if(tort<hare )
cout<<"Hare wins. Yuch. ";
else
cout<<"Would you believe IT'S A TIE!! ";
cout<<"time of race: "<<rtime<<" simulated seconds ";
system("pause");
return 0;
}
void print(int* t,int* h)
{if(*h==*t)
cout <<setw(*h)<<"OUCH!!!";
else if(*h<*t)
cout<<setw(*h)<<'H'<<setw(*t-*h)<<'T';
else
cout<<setw(*t)<<'T'<<setw(*h-*t)<<'H';
cout<<endl;
}
void movehare(int* r )
{int num;
num=rand()%10;
if(num<2)
*r-=2;
else if(num<5)
*r++;
else if(num<6)
*r-=12;
else if(num<8)
*r+=9;
if(*r< 1 )
*r=1;
}
void movetort(int* t)
{int num;
num=rand()%10;
if(num<5)
*t+=3;
else if(num<7)
*t-= 6;
else
*t++;
if(*t<1)
*t=1;
}
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