Using the Round Robin Scheduler principle, write the algorithm to display the ca

Question

Using the Round Robin Scheduler principle, write the algorithm to display the calendar of January 2012. The first day of January of the new year will be a Sunday

Hints:
- You create an array A of 7 singly linked lists of integers (1 to 31), where array A[0] is the list of Sundays, … A[5] is the list of Fridays, A[6] is the list of Saturdays.
You may then use A[i].Displays method to display a list

- Should have a good Java Class on Singlylinkedlist of Integer or generic.

- Should have a Java class Queue of integers implemented by Arrays or linkedlist.

- Should be able to create an Array of 7 Linkedlist, example:
Queue queue = new Queue();
SLinkedList [] a = new SLinkedList[7];
for (int i=0; i<7; i++)
{
a[i]= new SLinkedList();
}


i=0 corresponds to Sundays
i=1 to Mondays,
...
i=6 to Saturdays,

Explanation / Answer

Answer Details #include #include #include "scaldate.h" /* ** calendar generation information */ int days[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; char *month[12] = {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}; char *daynames[8] = {"Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat", "Sun"}; /* ** box drawing stuff */ #if defined(MSDOS) || defined(_WIN32) const char *topborder = "ÕÍÍÍÍÍÍÍÍÍÍÍ" "ÍÍÍÍÍÍÍÍÍÍÍÍ" "ÍÍÍ͸"; const char *midborder = "ÆÍÍÍÍÍÍÍÍÍÍÍ" "ÍÍÍÍÍÍÍÍÍÍÍÍ" "ÍÍÍ͵"; const char *botborder = "ÔÍÍÍÍÍÍÍÍÍÍÍ" "ÍÍÍÍÍÍÍÍÍÍÍÍ" "ÍÍÍ;"; const char *line = "³"; #else const char *line = ""; #endif /* ** tell 'em they messed up */ void usage(void) { puts("Usage: CAL [m y]"); puts("where: m = month (1 - 12)"); puts(" y = year (1 - 99, 1800 - 3000)"); exit(-1); } /* ** here's where the real work's done */ int main(int argc, char *argv[]) { int day, day_1, numdays, i, j; unsigned yr, mo; if (argc < 3 && argc > 1) usage(); if (argc >= 3) { yr = atoi(argv[2]); mo = atoi(argv[1]); } else { long dnow = today(); unsigned dy; scalar_to_ymd(dnow, &yr, &mo, &dy); } if (!mo || 12 yr) yr += 1900; if (3000 yr) usage(); for (i = 0, mo -= 1; i < 3; ++i, ++mo) { if (!mo) { mo = 12; --yr; } if (12

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