Using the Rydberg equation, the wavelength, in nm, of the line in the Balmer ser

Question

Using the Rydberg equation, the wavelength, in nm, of the line in the Balmer series corresponding to the transition to n = 6 is:

A. ~93 nm

B. ~274 nm

C. ~411 nm

D. ~7467 nm

E. Longer than 7500 nm

The intracellular potassium ion concentration in a human neuron is 0.150 M. The extracellular potassium ion concentration is 0.005 M. Calculate the membrane potential (EM+) of the neuron at 37 degree celcius

. A. -1.50 V B. -0.09 V C. 0.00 V D. 0.09 V E. 1.50 V

Determine the pH of a buffer solution that contains 0.35 M NH3 and 0.5 M NH4Cl. (Kb (NH3) = 1.8 × 10-5)

A. 12.3 B. 9.1 C. 4.9 D. 4.3 E. 0.43

Consider the following galvanic cell: Zn | Zn2+ || MnO4 - | Mn2+ Use the standard reduction potentials to determine the cell potential when it is operated at pH = 2 with [MnO4 - ] = 0.12 M, [Mn2+] = 0.0010 M and [Zn2+] = 0.015 M at 25 degree celcius

. A. 2.36 V B. 2.03 V C. 2.25 V D. 2.52 V E. 2.14 V

What is the oxidation state of the metal ion in [CrCl2(H2O)4]Cl and how many stereoisomers are possible?

Explanation / Answer

1)

for Balmer series, final value of n=2

Here photon will be emitted

1/wavelength = R* (1/nf^2 - 1/ni^2)

R is Rydberg constant. R = 1.097*10^7

1/wavelength = R* (1/nf^2 - 1/ni^2)

1/wavelength = 1.097*10^7* (1/2^2 - 1/6^2)

wavelength = 4.11*10^-7 m

wavelength = 411 nm

Answer: C

Feel free to comment below if you have any doubts or if this answer do not work

Only 1 question at a time please

Related Questions

Navigate

• Browse (All)
• Browse U
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.