Complete the body of this method. You do not need to check the precondition. You

Question

Complete the body of this method. You do not need to check the precondition. You may use the CharStack class.public static boolean balanced(String p) // Precondition: Each character of p is '(', ')', '{' or '}'. // Postcondition: The method returns true if the characters form a // sequence of correctly balanced parentheses with each '(' matching // a ')' and each '{' matching a '}'. Note that a sequence such as // ( { ) } is NOT balanced because when we draw lines to match the // parentheses to their partners, the lines cross each other. On the // other hand, ( { } ) and { ( ) } are both balanced.

Explanation / Answer

import java.util.Scanner; import java.util.Stack; public class PatternCheck { static String pattern; static Stack s = new Stack(); public static void main(String[] args) { int flag1 = 0, flag2 = 0; char character; char popedChar; System.out.println("Enter your pattern"); Scanner input = new Scanner(System.in); pattern = input.nextLine(); for (int i = 0; i

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