Problem: My code so far: Any help is appreciated thanks! Solution using the foll

Question

Problem:

My code so far:

Any help is appreciated thanks!

Explanation / Answer

using the following code you can convert int into words. Use these functions in you program #include #include char *ordinal (char buf[1024], int value); int main (int argc, char *argv[]) { char buf[1024]; if (argc != 2) { printf ("usage: ordinal "); return EXIT_FAILURE; } ordinal (buf, atoi (argv[1])); puts (buf); return EXIT_SUCCESS; } /* Works for positive and negative numbers up to 9 digits long, if you speak American English. */ char * ordinal (char buf[1024], int value) { static const char *const powers[] = {"thousand", "million", "billion"}; static const char *const ones[] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"}; static const char *const tens[] = {"twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"}; char *cp = buf; if (value < 0) { cp += sprintf (cp, "negative "); value = -value; } else if (value == 0) { strcpy (buf, "zero"); return buf; } { int part_stack[4]; int *part_ptr = part_stack; for (; value; value /= 1000) *part_ptr++ = value % 1000; while (part_ptr > part_stack) { int p = *--part_ptr; if (p >= 100) { cp += sprintf (cp, "%s hundred ", ones[p / 100 - 1]); p %= 100; } if (p >= 20) { if (p % 10) cp += sprintf (cp, "%s-%s ", tens[p / 10 - 2], ones[p % 10 - 1]); else cp += sprintf (cp, "%s ", tens[p / 10 - 2]); } else if (p > 0) cp += sprintf (cp, "%s ", ones[p - 1]); if (p && part_ptr > part_stack) cp += sprintf (cp, "%s ", powers[part_ptr - part_stack - 1]); } } cp[-1] = 0; return buf; } /* Local variables: compile-command: "gcc -W -Wall -ansi -pedantic ordinal.c -o ordinal" End: */

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.