THIS IS A MATLAB QUESTION. The statement given below calculates the roots of 4x^

Question

THIS IS A MATLAB QUESTION.

The statement given below calculates the roots of 4x^3-12x^2+x-3.

Use the "if construct" to determine if each root is the real or complex. Use the MATLAB

command "isreal" to check each of the 3 roots, one root at a time. "isreal" returns

a 1 if real, a zero if not. Example: isreal(4)=1 isreal(4+2i)=0. [6]  

As part of the if statement use fprintf to display a message like "Root number 2 is

complex". Note that "2" is a counter in your loop - not the root value. [2]

Put your "if" construct in a "for" loop so you can check all of the roots [2].

  
p=[4 -12 1 -3];
r=roots(p)

  
% start your "for" loop here
for i=1:length(r)
if isreal r(i)
fprintf(' The root number %g is real ',r(i))
else
fprintf(' The root number %g is complex ',r(i))
end
end
  
fprintf(' ');

I believe it's all correct , except I'm using isreal incorrect. Could someone help, so I can finish this code. Thanks

Explanation / Answer

all of your code is correct but use brackets() at isreal replace your code "if isreal r(i)" with "if isreal(r(i))"

the modified script is:--

p=[4 -12 1 -3];
r=roots(p);
% start your "for" loop here
for i=1:length(r)  
    if isreal(r(i))   %i have changed your code in this line
        fprintf(' The root number %g is real ',r(i));
    else
        fprintf(' The root number %g is complex ',r(i));
    end
end
fprintf(' ');

output is:--

>> roots_isreal

The root number 3 is real

The root number -6.93889e-18 is complex

The root number -6.93889e-18 is complex

>>

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