Computer Dynamics Computer Dynamics is a microcomputer software development comp

Question

Computer Dynamics Computer Dynamics is a microcomputer software development company that has a 300-computer network. The company is located is in three adjacent five-story buildings in an office park, with about 100 computers in each building. The 2 LANs in each building are similar, but one build has the data center on the second floor. There t are no other office locations. The current network is poorly designed for its current needs and must be 1 completely replaced. Develop a logical design for this IV. enterprise campus that considers the seven network architecture components. There are no other campuses, so you can omit WAN access. You will need to make some assumptions, so be sure to document your assumptions and explain why you have designed the network in this way.

Explanation / Answer

For this question, we need to assign the IP addresses to company's computer network.

Things to keep in mind.
1. We need to pick the set of private IP addresses range because company employees need to communicate with each other. So if we want to communicate with in LAN network only then we use private IP address range
   Private IPV4 Address Ranges are as follows
(1.1) 10.0.0.0 – 10.255.255.255
   (1.2)   172.16.0.0 – 172.31.255.255
   (1.3) 192.168.0.0 --192.168.255.255

2. Here we use the concept of subnetting to divide the network between buildings and for effective utilisation of IP address.

Niumber of buildings = No. of Subnets = 3
Number of computers on each building = No of hosts required = 100

2^n - 2 = Number of subnest , where n is number of subnet bits

2^n - 2 = 3 ,
So n = 3 is best suited value
So we need 3 subnet bits

No of bits required for host
2^2 - 2 = 100
So n = 7 is best suited value

So total bits required for management is 7 + 3 = 10 and minimum loss of IP address we use range 192.168.0.0

So Network Id of whole Network is 192.168.252.0 and it iwll be assigned to data center.

So Network ID of first subnet is 192.168.252.128
First IP address of first building is 192.168.252.129
Last address of First building is 192.168.252.228
Remaining 25 address will be unassigned which can be used in future in first building.

So Network ID of 2nd subnet is 192.168.253.0
First IP address of first building is 192.168.253.1
Last address of First building is 192.168.253.100
Remaining 25 address will be unassigned which can be used in future in 2nd building.

So Network ID of first subnet is 192.168.253.128
First IP address of first building is 192.168.253.129
Last address of First building is 192.168.253.228
Remaining 25 address will be unassigned which can be used in future in first building.

THis is how we can manage the network

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