Can you help make my code take and call more names in line. Right now it only ca

Question

Can you help make my code take and call more names in line. Right now it only calls 2 names. PLEASE add comments

(( output should look like this ))
0.Call a custmer
1.Add a customer
2.Quit
Enter your choice: 1
Enter the customer name to be placed in call: tom
0.Call a custmer
1.Add a customer
2.Quit
Enter your choice: 1
Enter the customer name to be placed in call: peter
0.Call a custmer
1.Add a customer
2.Quit
Enter your choice: 1
Enter the customer name to be placed in call: bob
0.Call a custmer
1.Add a customer
2.Quit
Enter your choice: 0
Name of the customer in line: tom
0.Call a custmer
1.Add a customer
2.Quit
Enter your choice: 0
Name of the customer in line: peter
0.Call a custmer
1.Add a customer
2.Quit
Enter your choice: 0
Name of the customer in line: bob
0.Call a custmer
1.Add a customer
2.Quit
Enter your choice: 2

Explanation / Answer

PROGRAM CODE:

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

struct node
{
   char name[50];
   struct node*next;
};
typedef struct node Node;
Node *list;

int main(void) {
   int choice;
   do
   {
       printf(" 0. call 1. Add 2. Exit");
       printf(" Enter your choice: ");
       scanf("%d", &choice);
       if(choice == 0)
       {
           if(list == NULL)
           {
               printf("List is empty ");
           }
           else
           {
               Node *temp;
               printf(" Name of the customer in line: %s ", list->name);
               if(list->next != NULL)
               {
                   temp = list->next;
                   free(list);
                   list = temp;
               }
               else
               list = NULL;
           }
       }
       else if(choice == 1)
       {
           char str[50];
           Node *temp;
           printf(" Enter the customer name to be placed in the call: ");
           scanf("%s", str);
           temp = (Node*)malloc(sizeof(Node));
           strcpy(temp->name, str);
           temp->next = NULL;
           if(list == NULL)
           {
               list = temp;
           }
           else
           {
               //Made changes only here to keep on adding more names
               Node *temp1 = list;
               while(temp1->next != NULL)
                   temp1 = temp1->next;
               temp1->next = temp;
           }
       }
   }while(choice != 2);
   return 0;
}

OUTPUT:

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.