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A binomial tree is a special kind of rooted tree used for various data structure

ID: 3837684 • Letter: A

Question

A binomial tree is a special kind of rooted tree used for various data structures in computer science. A degree d binomial tree can be defined recursively as follows. A degree 0 binomial tree is a single vertex with no edges. A degree d binomial tree has a root vertex with out-degree d. The first (that is, left most) subtree is a degree d - 1 binomial tree. The second (that is, second to left) subtree is a degree d - 2 binomial tree. Continue on in this way so that the last (rightmost) subtree is a degree 0 binomial tree. (a) What is the height of a degree d binomial tree? Prove your result by induction on d. (b) Write a recurrence for the number of nodes N(d) in a binomial tree of degree d. (c) Use the guess-and-check method to guess a formula for N(d). Prove that your formula holds by induction on d.

Explanation / Answer

A binomial tree of degree d is two binomial tree of degree d-1 joined by on edge, the
root of one is the leftmost child of the root of the other

like this

           o
           /|
          o o
          |
          o
      
       binomial tree of degree 2 is two binomial tree of degree 1 joined by one edge. the
       root of one is the leftmost child of the root of the other

Q 1
Proof 1)
       Height of degree d binomial tree is d
       proof by induction
      
       Height(0) = 0
       Height(1) = 1
       Assume Height(k) = k
       Now, Height (k + 1) = A binomial tree of degree k+1 is two binomial tree of degree k joined by one edge,the
       root of one is the leftmost child of the root of the other. So, this will increase height of tree by 1
           so, Height(k + 1) = Height(k) + 1
                              = k + 1
       Thus, Height of degree d binomial tree is d
      
Q 2)
       N(d) = 2^d
      
Q 3)
      
       No of nodes in degree d binomial tree is 2^d
       proof by induction
      
       N(0) = 1
       N(1) = 2
       Assume N(k) = 2^k
       Now, N(k + 1) = A binomial tree of degree k+1 is two binomial tree of degree k joined by one edge,
           so, N(k + 1) = N(k) + N(k)
                       = 2^k + 2^k
                       = 2^(k+1)
               N(d)   = 2^d
       Thus, No of nodes in degree d binomial tree is 2^d

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