QUESTION 28 In the following code, why is node assigned before root is deleted?

Question

QUESTION 28 In the following code, why is node assigned before root is deleted? while (e root node Next delete root root node O values of deleted variables cannot be accessed o the return of the getNext0 method needs to be saved the get Next0 method call would be invalid after the delete o all of the above o none of the above QUESTION 29 MA: A class definition introduces a new into the program type name instance namespace standard definition QUESTION 30 MA: A dynamic array is allocated with a new statement deleted with a delete statement allocated at the beginning of a block turned to the stack when it goes out of scope not limited to the scope of the block in which it is allocated

Explanation / Answer

28.
   Option C is correct.
   Once deleted, root will point to nothing. This function call would fail

29. Option A,C,D
   Not instance, class objects are instances

30. Option A,B,C,E

26. Option A ( default, assignment, copy constructors )

27. Complete would be :
   for(
   vi = vm.begin();
   vi != vm.end();
   ++vi
   )
   {
   std::cout
   << vi->first
   << std.endl;
   }

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